JEE Main Integration Practice Test 2026 – Complete Exam Prep Guide

To find the integral of the function \( x^2 + 3x + 2 \), we use the power rule of integration, which states that the integral of \( x^n \) is \( \frac{x^{n+1}}{n+1} + C \) for any constant \( n \neq -1 \).

Applying this rule to each term in the polynomial:

1. For the term \( x^2 \):

- The integral is \( \frac{x^{2+1}}{2+1} = \frac{x^3}{3} \).

2. For the term \( 3x \):

- The integral is \( 3 \cdot \frac{x^{1+1}}{1+1} = 3 \cdot \frac{x^2}{2} = \frac{3}{2}x^2 \).

3. For the constant term \( 2 \):

- The integral is \( 2x \) because the integral of a constant \( a \) is \( ax \).

Putting it all together, we have:

\[

\int (x^2 + 3x + 2) \, dx = \frac